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Decomposition of the product of irreducible elements

I’m stuck at the following problem:
Problem Let $f,g\in\mathbb{Z}[x]$ be irreducible polynomials, such that $f e g$. Show that the product $fg$ can be expressed as a product of $f$ and $g$ with irreducible polynomials as factors.
Attempt: The decomposition of the product is simply given by the Chinese Remainder Theorem. Hence it is enough to show that the ring of polynomials over $\mathbb{Z}$ (or $\mathbb{Z}[x]$, doesn’t matter) is a UFD. It is not hard to show that the ring is an integral domain. So all we need to show is that it is a UFD.
Let $f,g\in\mathbb{Z}[x]$ be irreducible and let $A=\mathbb{Z}[x]/(f)$ and $B=\mathbb{Z}[x]/(g)$. I’m trying to show that the ideal $(f,g)$ is prime, but I don’t see why it should be so.
Let $\pi_A\colon \mathbb{Z}[x]\to A$ be the canonical homomorphism. We want to

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The federal government began accepting applications Thursday for low-income Texans to get health insurance this year through the so-called Affordable Care Act, setting in motion a difficult new reality for many Americans.

“As you start to sign up for the marketplace, you will know things about yourself: whether you are young, old, a man or woman, healthy or ill, you know things about yourself — your income, your family size, your health and your history,” Health and Human Services Secretary Kathleen Sebelius said in an online video announcing the launch.

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All of that adds to the pressure on the Obama administration, which is trying to make health care coverage more affordable for millions of uninsured Americans.

Public and private enrollment began Oct. 1. In some states, the exchanges will begin providing coverage for millions of Texans on Jan. 1. But those states will be slower to provide coverage than others.

“The federal government is setting a very ambitious timeline for states to have their exchanges up and running,” said John T. Chambers, former president of the U.S. Chamber of Commerce and a former CEO of Cisco Systems.

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